문제 난이도 : Easy
문제 유형 : Data Structures - Linked Lists
문제 설명 간략 :
두 Linked List를 비교하여 요소가 모두같고 길이도 같으면 return 1 아니면 return 0.
제약사항
- 1 <= t <= 10
- 1 <= n,m <= 1000
- 1 <= list[i] <= 1000, where list[i] is the ith element of the linked list
자바 풀이
import java.io.*;
import java.math.*;
import java.text.*;
import java.util.*;
import java.util.regex.*;
public class Solution {
static class SinglyLinkedListNode {
public int data;
public SinglyLinkedListNode next;
public SinglyLinkedListNode(int nodeData) {
this.data = nodeData;
this.next = null;
}
}
static class SinglyLinkedList {
public SinglyLinkedListNode head;
public SinglyLinkedListNode tail;
public SinglyLinkedList() {
this.head = null;
this.tail = null;
}
public void insertNode(int nodeData) {
SinglyLinkedListNode node = new SinglyLinkedListNode(nodeData);
if (this.head == null) {
this.head = node;
} else {
this.tail.next = node;
}
this.tail = node;
}
}
public static void printSinglyLinkedList(SinglyLinkedListNode node, String sep, BufferedWriter bufferedWriter) throws IOException {
while (node != null) {
bufferedWriter.write(String.valueOf(node.data));
node = node.next;
if (node != null) {
bufferedWriter.write(sep);
}
}
}
// Complete the compareLists function below.
/*
* For your reference:
*
* SinglyLinkedListNode {
* int data;
* SinglyLinkedListNode next;
* }
*
*/
static boolean compareLists(SinglyLinkedListNode head1, SinglyLinkedListNode head2) {
boolean equal = true;
try {
while(head1 != null) {
if(head1.data != head2.data) {
equal = false;
break;
}
head1 = head1.next;
head2 = head2.next;
}
} catch (Exception e) {
equal = false;
}
return equal;
}
private static final Scanner scanner = new Scanner(System.in);
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