문제 난이도 : Easy

문제 유형 : Data Structures - Linked Lists

문제 설명 간략 :

두 Linked List가 주어지고 두개를 정렬된 하나의 Linked list로 만들어라.

제약사항

• 1 <= t <= 10
• 1 <= n,m <= 1000
• 1 <= list[i] <= 1000, where list[i] is the i^th element of the linked list

자바 풀이

import java.io.*;
import java.math.*;
import java.security.*;
import java.text.*;
import java.util.*;
import java.util.concurrent.*;
import java.util.regex.*;

public class Solution {

    static class SinglyLinkedListNode {
        public int data;
        public SinglyLinkedListNode next;

        public SinglyLinkedListNode(int nodeData) {
            this.data = nodeData;
            this.next = null;
        }
    }

    static class SinglyLinkedList {
        public SinglyLinkedListNode head;
        public SinglyLinkedListNode tail;

        public SinglyLinkedList() {
            this.head = null;
            this.tail = null;
        }

        public void insertNode(int nodeData) {
            SinglyLinkedListNode node = new SinglyLinkedListNode(nodeData);

            if (this.head == null) {
                this.head = node;
            } else {
                this.tail.next = node;
            }

            this.tail = node;
        }
    }

    public static void printSinglyLinkedList(SinglyLinkedListNode node, String sep, BufferedWriter bufferedWriter) throws IOException {
        while (node != null) {
            bufferedWriter.write(String.valueOf(node.data));

            node = node.next;

            if (node != null) {
                bufferedWriter.write(sep);
            }
        }
    }

    // Complete the mergeLists function below.

    /*
     * For your reference:
     *
     * SinglyLinkedListNode {
     *     int data;
     *     SinglyLinkedListNode next;
     * }
     *
     */
    static SinglyLinkedListNode mergeLists(SinglyLinkedListNode head1, SinglyLinkedListNode head2) {

        if(head1 == null) {
            return head2;
        } else if(head2 == null) {
            return head1;
        }

        if(head1.data < head2.data) {
            head1.next = mergeLists(head1.next, head2);
            return head1;
        } else {
            head2.next = mergeLists(head1, head2.next);
            return head2;
        }

    }

    private static final Scanner scanner = new Scanner(System.in);

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